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| > var path = require('path')
undefined
> path.resolve('./11')
'/home/witt/11'
> path.resolve('111')
'/home/witt/111'
> path.resolve('../1111')
'/home/1111'
> path.resolve('root','111')
'/home/witt/root/111'
> path.resolve('/root','111')
'/root/111'
> path.resolve('/root/','/111/')
'/111'
> path.resolve('a','/b','c')
'/b/c'
|
由上面可以知道，字符串是可以拼接路徑的
path.resolve可以接受多個參數來進行拼接路徑，當它沒有參數時測輸出當前路基
如果是有參數加入
./和字符前面不加符号代表和当前路径进行拼接
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| > path.resolve('./11')
'/home/witt/11'
> path.resolve('111')
'/home/witt/111'
|
只有斜杠/代表绝对路径，当有多个参数时候，有多个绝对路径，以最后一个为主，和后面的进行拼接
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| > path.resolve('/root','111')
'/root/111'
> path.resolve('/root/','/111/')
'/111'
> path.resolve('a','/b','c')
'/b/c'
|
当出现两个点加一个斜杠../当回到上一个目录
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| > path.resolve()
'/home/witt' //输出的是当前目录
> path.resolve('../1111')
'/home/111'
|